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# Even sum in array

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For (int num : array ) Here int is data type for num variable where you want to store all arrays data in otherwords you can say the destination where you want to give all component of arrays. Here array is the name of the array itself. So all arrays components we are giving to num variable. Even sum subsequence means the subsequence whose total sum( sum of all the elements in the subsequence) is divisible by 2. And for odd sum subsequence, the total sum leaves a remainder of 1 when divided by 2. Note: 1) In general, for an array of size 'N', there are (2 ^ 'N' - 1) non-empty subsequences possible. n = int (input ("Enter the size of the array: ")) print ("Enter the Element of the array:") for i in range (0,n): num = int (input ()) arr.append (num) print ("Sum of even Element is:",SumOfEvenElement (arr,n)) Input/Output: Enter the size of the array: 3. Enter the Element of the array:.

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n = int (input ("Enter the size of the array: ")) print ("Enter the Element of the array:") for i in range (0,n): num = int (input ()) arr.append (num) print ("Sum of even Element is:",SumOfEvenElement (arr,n)) Input/Output: Enter the size of the array: 3. Enter the Element of the array:.

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We will traverse the array using two for loops for each number of pairs. Now calculate sum, if it is even increment count by 2 for even sums else increment count by 2 for odd sums. Let’s understand with examples. Input− Arr[]= { 1,1,2,3 } N=4. Output− Count of even product sums − 6 Count of odd sum pairs − 6.

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Basically, the formula to find the sum of even numbers is n (n+1), where n is the natural number. We can find this formula using the formula of the sum of natural numbers, such as: S = 1 + 2+3+4+5+6+7+n. S= n (n+1)/2. To find the sum of consecutive even numbers, we need to multiply the above formula by 2. Hence,.

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This approach takes O(n 3) time as the subarray sum is calculated in O(1) time for each of n 2 subarrays of an array of size n, and it takes O(n) time to print a subarray.. 2. Hashing. We can also use hashing to find subarrays with the given sum in an array by using a map of lists or a multimap for storing the end index of all subarrays having a given sum. The idea is to traverse the given.

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The above code creates an array of numbers named arr1.The res variable is initialized to store the sum of elements. After that, the for loop is exercised in the following manner: the variable “i” is initialized at “i=0“ the looping condition is “i < arr1.length” which states that the loop will run until the value of “i” is less than the length of arr1.

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